Answer: 0.5263
Step-by-step explanation:
Given : The completion times for a job task range from 11.8 minutes to 19.4 minutes .
The density function for uniform distribution function for interval [a,b] :-
[tex]f(x)=\dfrac{1}{b-a}[/tex]
Then the density function for the given situation:-
[tex]f(x)=\dfrac{1}{19.4-11.8}=\dfrac{1}{7.6}[/tex]
The required interval : [tex]16.8-12.8=4[/tex]
Now, the probability that it will require between 12.8 and 16.8 minutes to perform the task will be :-
[tex]\dfrac{4}{7.6}=0.526315789474\approx0.5263[/tex]
