Answer:
Step-by-step explanation:
Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.
a) The sum is 4 on each of the three rolls.
(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12
Prob for getting same sum 4 in 3 rolls = [tex](\frac{1}{12} )^3[/tex]
(since each trial is independent)
b) Prob sum =4 in exactly 2 rolls
= [tex]3C2 (1/12)^2 (11/12)[/tex]=[tex]\frac{33}{12^3}[/tex]
