Answer:
Option C.
Step-by-step explanation:
We can solve this question by plugging in the values of x and y in the given equations of the options.
A). y = [tex]\frac{5}{4}x[/tex]
Now we plug in the value of x = 100 and y = 135
135 = [tex]\frac{5}{4}\times 100[/tex]
135 = 125
Which is not possible so this equation is not the answer.
B). y = [tex]\frac{4}{5}x[/tex]
We plug in the value of x = 100 and y = 135
135 = [tex]\frac{4}{5}\times 100[/tex]
135 = 80
Again not possible. So this equation is not the required answer.
C). y = [tex]\frac{5}{4}x+10[/tex]
For x = 100 and y = 135
135 = [tex]\frac{5}{4}\times 100+10[/tex]
135 = 125 + 10
135 = 135
For x = 200 and y = 260
260 = [tex]\frac{5}{4}\times 200+10[/tex]
260 = 250 + 10
260 = 260
Therefore, the given table satisfies this equation for all values of x and y given in the table.
Option C. is the answer.
D). y = [tex]\frac{4}{5}x+55[/tex]
For x = 100 and y = 135
135 = [tex]\frac{4}{5}\times 100+55[/tex]
135 = 80 + 55
135 = 135
Now for x = 200 and y = 260
260 = [tex]\frac{4}{5}\times 200+55[/tex]
260 = 160 + 55
260 = 215
Which is not possible therefore option D is not the answer.
