Answer:
The filament should be 0.02935 m in order to radiate 60 W of power.
Explanation:
if A is the area of the filament, e is the emmisivity and T is the temperature of the filament then the power P is given by the stefan boltzmann power equation given by:
P = σ×A×e×T^4
A = P/(σ×e×T^4)
= (60)/[(5.67×10^-8)×(1.0)×(3000 + 273)^4]
= 9.22×10^-6 m^2
but if L is the length of the filament and d is the diameter of the filament then Area A is given by:
A = 2π×d×L
L = A/(2π×d)
= (9.22×10^-6)/(2π×(0.050×10^-3))
= 0.02935 m
Therefore, the filament should be 0.02935 m in order to radiate 60 W of power.
