Answer:
[tex]CoCl_{2}.(H_{2}O)_{6}[/tex] is formed and it has three unpaired electrons.
Explanation:
Blue [tex]CoCl_{2}[/tex] reacts with water to produce pink colored [tex]CoCl_{2}.(H_{2}O)_{6}[/tex] complex.
In this complex, [tex]Co^{2+}[/tex] ion forms an octahedral complex with six [tex]H_{2}O[/tex] ligands.
As [tex]H_{2}O[/tex] is a weak field ligand therefore [tex]Co^{2+}[/tex] ion remains in low spin state.
Hence electronic configuration of [tex]Co^{2+}[/tex] ion in this octahedral geometry is [tex]t_{2g}^{5}e_{g}^{2}[/tex] with total three unpaired electrons.
