Leslie made a chocolate milkshake in the blender for her daughter milkshake occupies just a little more than 50 in.³ of space in the blender pitcher. when serving milkshake to her daughter she has three glasses to choose from, determine whether or not each of the three glasses is large enough to contain all of the chocolate milkshake that was made for her daughter . use 3.14 to approximate pi .
Glass A. with a height of 4 inches and the diameter of 3.5 inches is too small or large enough...Glass B with a height of 5 inches and the radius of 1.9 inches is too small or large enough...Glass C with a height of 6 inches and the radius of 1.5 inches is...too small or large enough

Respuesta :

Answer:

Glass A is too small, Glass B is large enough and Glass C is too small ....

Step-by-step explanation:

Glasses are cylindrical in shape. Thus the formula is:

V = π r² h

For Glass A:

r = d/2 = 3.5/2

r = 1.75

h = 4 inches

Now substitute the values in the formula:

V= 3.14*(1.75)^2 * 4

V= 3.14*3.0625*4

V= 38.465 in.³ < 50in.³

For Glass B:

V = π r² h

where h = 5 inches

r = 1.9 inches

Plug the values in the formula:

V=3.14*(1.9)^2*5

V= 56.677 in³ > 50in³

For Glass C:

V = π r² h

where h=6 inches

r = 1.5 inches

Plug the values in the formula:

V= 3.14*(1.5)^2*6

V= 42.39 in³ < 50 in³

Therefore Glass A is too small, Glass B is large enough and Glass C is too small ....

Answer:

Glass A is too small.

Glass B is large enough.

Glass C is too small.

Step-by-step explanation:

Assuming that the glasses are cylindrical, we need to use the following formula for calculate volume of a cylinder:

[tex]V=\pi r^2h[/tex]

Where "r" is the radius and "h" is the height.

Now, we can calculate the volume of each glass:

Glass A

We know that:

[tex]r=\frac{3.5in}{2}=1.75in\\\\h=4in[/tex]

Then (Using [tex]\pi=3.14[/tex]):

[tex]V_A=3.14(1.75in)^2(4in)=38.46in^3[/tex]

Glass A is too small.

Glass B

We know that:

[tex]r=1.9in\\\\h=5in[/tex]

Then (Using [tex]\pi=3.14[/tex]):

[tex]V_B=3.14(1.9in)^2(5in)=56.67in^3[/tex]

Glass B is large enough.

Glass C

We know that:

[tex]r=1.5in\\\\h=6in[/tex]

Then (Using [tex]\pi=3.14[/tex]):

[tex]V_C=3.14(1.5in)^2(6in)=42.39in^3[/tex]

Glass C is too small.