Respuesta :
Answer:
C.(0,1),(-3,-2)
Step-by-step explanation:
(x+1)=x^2+4x+1
0=x^2+3x
(x+3)(x+0)
x=-3 x=0
when x=-3, y=(3)^2+4(-3)+1=-2
when x=0, y=0^2+0x+1=1
Answer:
C
Step-by-step explanation:
We can substitue equation 2 into equation because y is common in both equations:
1. y=x^2+4x+1
2. y=x+1
therefore:
[tex]x+1=x^2+4\cdot{x}+1[/tex]
We can take x+1 to the right side:
[tex]0=x^2+3\cdot{x}[/tex]
We can write it as multiples of x:
[tex]0=x\cdot{(x+3)}[/tex]
Therefore the answer is x=0 or x=-3 and therefore we can substitute into equation 1 and 2. therefore for equation 1 and 2 when x=0
[tex]y=1[/tex]
and when x=-3
[tex]y=-2[/tex]
The answer is (0,1) and (-3,-2) which is C
