Respuesta :
Answer:
Sin θ = +/-√5/3 and tan θ = +/- √5/2.
Step-by-step explanation:
OK so we have a right triangle in the first quadrant of the unit circle with one angle θ whose cosine is 2/3.
That means that the adjacent side = 2 and the hypotenuse = 3.
So, by Pythagoras, the opposite side = √(3^2 - 2^2) = +/-√5.
So sin θ = +/-√5/3 and tan θ = +/-√5/2.
* The +/- results from the fact that the triangle may be in the first quadrant or the fourth where the cosine is positive. The sine and tangent are positive in the first quadrant but negative in the fourth.
The value of sinθ = √5 / 3 and the value of tanθ = √5 / 2.
What are the values of different trigonometric functions?
sinθ = P / H cosθ = B / H tanθ = P / B
cosecθ = H / P secθ = H / B cotθ = B / P
Given trigonometric function in the question:
cosθ = 2 / 3
cosθ = B / H
B / H = 2 / 3
H^2 = P^2 + B^2
(3)^2 = P^2 + (2)^2
9 = P^2 + 4
P^2 = 5
P = √5
The value of sinθ = P / H
sinθ = √5 / 3
The value of tanθ = P / B
tanθ = √5 / 2
Hence, the value of sinθ = √5 / 3 and the value of tanθ = √5 / 2.
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