bradley dropped the ball from a roof 16 feet high. Each time the ball hits the ground, it bounces3/5 the previous height. Find the height the ball will bounce after hitting the ground the fourth time.

According to the given statement Bradley dropped the ball from a roof 16 feet high.Each time the ball hits the ground, it bounces3/5 the previous height

Therefore,

First bounce = 16*3/5 = 9.6

Second bounce = 9.6 *3/5 = 5.76

Third bounce = 5.76*3/5=3.456

Fourth bounce = 3.456*3/5=2.0736

The height the ball will bounce after hitting the ground the fourth time = 2.0736ft....

slicergiza slicergiza · Answer 2 · 2019-08-29T12:41:32+02:00

Answer:

2.0736 feet

Step-by-step explanation:

Given,

The height of the roof = 16 feet,

∵ Each time the ball hits the ground, it bounces 3/5 the previous height,

So, the height bouches by ball after first hitting from the ground = [tex]\frac{3}{5}(16)[/tex] feet,

In the second time, height = [tex]\frac{3}{5}(\frac{3}{5}(16))[/tex]

In third time, height = [tex]\frac{3}{5}(\frac{3}{5}(\frac{3}{5}(16))[/tex]

In fourth time, height = [tex]\frac{3}{5}(\frac{3}{5}(\frac{3}{5}(\frac{3}{5}(16))))[/tex]

[tex]=\frac{3\times 3\times 3\times 3\times 16}{5\times 5\times 5\times 5}[/tex]

[tex]=\frac{1296}{625}[/tex]

[tex]=2.0736\text{ ft}[/tex]