Respuesta :
Answer: The final temperature is [tex]279.8K[/tex]
Explanation:
[tex]heat_{absorbed}=heat_{released}[/tex]
As we know that,
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex] .................(1)
where,
q = heat absorbed or released
[tex]m_1[/tex] = mass of lead = 50 g
[tex]m_2[/tex] = mass of water = 75 g
[tex]T_{final}[/tex] = final temperature = ?
[tex]T_1[/tex] = temperature of lead = [tex]100^oC=373K[/tex]
[tex]T_2[/tex] = temperature of water = [tex]0^oC=273K[/tex]
[tex]c_1[/tex] = specific heat of lead = [tex]0.11kcal/kg^0C[/tex]
[tex]c_2[/tex] = specific heat of water= [tex]1.0kcal/kg^0C[/tex]
Now put all the given values in equation (1), we get
[tex]50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)][/tex]
[tex]T_{final}=279.8K[/tex]
Therefore, the final temperature of the mixture will be 279.8 K.
The study of chemicals and bonds is called chemistry. There are two types of elements are there and these are metals and nonmetals.
The correct answer is 279.8K.
What is specific heat?
- The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Specific heat is also sometimes referred to as massic heat capacity
The formula used to solve the question is as follows:-
[tex]Q=mct[/tex]
The data is given as follows:-
- m1= 50 g
- m2=75g
- T1= 373K
- T2= 273K
- C1=0.11
- C2=1.0
Place all the value in the equation and solve it
[tex]50*0.11*(T_{final}-373)=-[75*1.0*(T_{final}-273)\\T_2=279.8K[/tex]
Hence, the correct answer is 279.8k.
For more information about the specific heat, refer to the link:-
https://brainly.com/question/16759172
