Answer:
The heat is 10458 J and 15480 J.
Explanation:
Given that,
Temperature T₁ = 404 K
Temperature T₂ = 298 K
Work done = 2740 J
If the temperature T₁ =298 k
Temperature T₂ = 245 K
We need to calculate the heat
Using efficiency formula
[tex]\eta=\dfrac{W}{Q}[/tex]...(I)
We need to calculate the efficiency
Using formula of efficiency
[tex]\eta=1-\dfrac{T_{2}}{T_{1}}[/tex]
[tex]\eta=1-\dfrac{298}{404}[/tex]
[tex]\eta=0.262[/tex]
Put the value of efficiency in equation (I)
[tex]0.262=\dfrac{2740}{Q}[/tex]
[tex]Q=\dfrac{2740}{0.262}[/tex]
[tex]Q=10458\ J[/tex]
Again, we need to calculate the efficiency
[tex]\eta=1-\dfrac{T_{2}}{T_{1}}[/tex]
[tex]\eta=1-\dfrac{245}{298}[/tex]
[tex]\eta=0.177[/tex]
We need to calculate the heat
Using equation (I)
[tex]Q=\dfrac{2740}{0.177}[/tex]
[tex]Q=15480\ J[/tex]
Hence, The heat is 10458 J and 15480 J.
