What is the center and radius of the circle using radicals as needed?

Answer:
The center is (7,-2)
The radius is [tex]r=\sqrt{37}\ units[/tex]
Step-by-step explanation:
we know that
The equation of the circle in standard form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center and r is the radius
in this problem we have
[tex](x-7)^{2}+(y+2)^{2}=37[/tex]
therefore
The center is (7,-2)
The radius is
[tex]r^{2}=37\\ r=\sqrt{37}\ units[/tex]