In the future, astronomers discover a solid moon around a planet orbiting one of the nearest stars. This moon has a diameter of 1948 km and a mass of 1.6 × 1022 kg. What is its density?

Respuesta :

Answer:

The density is 4134.37 kg/m³.

Explanation:

Given that,

Diameter = 1948 km

Mass [tex]m=1.6\times10^{22}\ kg[/tex]

We need to calculate the volume of moon

[tex]V= \dfrac{4}{3}\pi\times r^3[/tex]

[tex]V=\dfrac{4}{3}\times\pi\times(974\times10^{3})^3[/tex]

[tex]V=3.870\times10^{18}\ m^3[/tex]

We need to calculate the density

[tex]\rho=\dfrac{m}{V}[/tex]

Where, m = mass

V = volume

Put the value into the formula

[tex]\rho=\dfrac{1.6\times10^{22}}{3.870\times10^{18}}[/tex]

[tex]\rho=4134.37\ kg/m^3[/tex]

Hence, The density is 4134.37 kg/m³.