The heights of a certain type of tree are approximately normally distributed with a mean height y = 5 ft and a standard
deviation = 0.4 ft. Which statement must be true?
O
A tree with a height of 5.4 ft is 1 standard deviation below the mean
A tree with a height of 4.6 ft is 1 standard deviation above the mean.
A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
A tree with a height of 6.2 ft is 3 standard deviations above the mean.

Respuesta :

Answer: Fourth Option:

"A tree with a height of 6.2 ft is 3 standard deviations above the mean"

Step-by-step explanation:

It is said that an X value is found Z standard deviations from the mean mu if:

[tex]\frac{X-\mu}{\sigma} = Z[/tex]

In this case we have that:

[tex]\mu=5\ ft[/tex]

[tex]\sigma=0.4\ ft[/tex]

We have four different values of X and we must calculate the Z-score for each

For [tex]X =5.4\ ft[/tex]

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

[tex]Z=\frac{5.4-5}{0.4}=1[/tex]

This means that: A tree with a height of 5.4 ft is 1 standard deviation above the mean

First Option: False

For [tex]X =4.6\ ft[/tex]

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

[tex]Z=\frac{4.6-5}{0.4}=-1[/tex]

This means that: A tree with a height of 4.6 ft is 1 standard deviation below the mean

Second Option: False

For [tex]X =5.8\ ft[/tex]

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

[tex]Z=\frac{5.8-5}{0.4}=2[/tex]

This means that: A tree with a height of 5.8 ft is 2 standard deviation above the mean

Third Option: False

For [tex]X =6.2\ ft[/tex]

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

[tex]Z=\frac{6.2-5}{0.4}=3[/tex]

This means that: A tree with a height of 6.2 ft is 3 standard deviations above the mean.

Fourth Option: True

Answer:

D. A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

edge2020