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With what type of electromagnetic radiation would you observe:

A star with a temperature of 5800 K?
A gas heated to a temperature of one million K?
A person on a dark night?

Respuesta :

Answer:

Green part of the visible spectrum.

X ray part of the electromagnetic spectrum.

Infrared part of the electromagnetic spectrum.

Explanation:

Wien's displacement law

[tex]\lambda_{max}=\frac{b}{T}[/tex]

Where, b = Wien's displacement constant = 2.898×10⁻³ mK

T = Temperature in kelvin

[tex]\lambda_{max}=\frac{2.898\times 10^{-3}}{5800}\\\Rightarrow\lambda_{max}=0.499\times 10^{-6}=0.5\mu m=500\ nm[/tex]

So, the wavelength would be of around the green part of the visible spectrum.

[tex]\lambda_{max}=\frac{2.898\times 10^{-3}}{1\times 10^6}\\\Rightarrow\lambda_{max}=2.898\times 10^{-9}=2.898\ nm[/tex]

So, the wavelength would be of around the X ray part of the electromagnetic spectrum.

Human body temperature = 37°C = 37+273.15 = 310.15 K

[tex]\lambda_{max}=\frac{2.898\times 10^{-3}}{37+273.15}\\\Rightarrow\lambda_{max}=\frac{2.898\times 10^{-3}}{310.15}\\\Rightarrow\lambda_{max}=9.34\times 10^{-6}=934\ nm[/tex]

So, the wavelength would be of around the Infrared part of the electromagnetic spectrum.

shubhamchouhanvrVT

The observed radiation would be  

(1)The green part of the visible spectrum.

(2)X-ray part of the electromagnetic spectrum.

(3)The infrared part of the electromagnetic spectrum.

What will be the observation of electromagnetic radiation?

From Wien's displacement law

[tex]\lambda_{max}=\dfrac{b}{T}[/tex]

Where, b = Wien's displacement constant = 2.898×10⁻³ mK

T = Temperature in kelvin

[tex]\lambda_{max}=\dfrac{2.898\times10^{-3}}{5800}[/tex]

[tex]\lambda_{max}=0.499\times10^{-6}[/tex]

[tex]\lambda_{max}=0.5nm[/tex]

So, the wavelength would be around the green part of the visible spectrum.

[tex]\lambda_{max}=\dfrac{2.898\times10^{-3}}{1\times10^6}[/tex]

[tex]\lambda_{max}=2.898nm[/tex]

So, the wavelength would be of around the X ray part of the electromagnetic spectrum.

[tex]\lambda_{max}=\dfrac{2.898\times10^{-3}}{37+273.15}[/tex]

[tex]\lambda_{max}=9.34\times10^{-6}=934nm[/tex]

Since the Human body temperature = 37°C = 37+273.15 = 310.15 K

So, the wavelength would be around the Infrared part of the electromagnetic spectrum.

Thus  The observed radiation would be  

(1)The green part of the visible spectrum.

(2)X-ray part of the electromagnetic spectrum.

(3)The infrared part of the electromagnetic spectrum.

To know more about electromagnetic radiation follow

https://brainly.com/question/15989804

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