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A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 65 Btu of heat is transferred to the water, and heat losses from the side walls amount to 8 Btu. The piston rises as a result of evaporation, and 5 Btu of work is done by the vapor. Determine the change in the energy of the water for this process.

Respuesta :

Answer:

dU = 52 kJ

Explanation:

Given:

During the process,

Heat transferred to water = 65 kJ

Heat loss from side = 8 kJ

Therefore, Resultant Heat transferred to water :

dQ = 65 KJ - 8K J = 57 kJ

Work done by the Vapour:

dW = 5 kJ

Let,

from thermo-dynamic first law

we have,

dQ = dU + d W

dU = dQ - dW

     =   57 kJ - 5 kJ    

     = 52 kJ

Thus, change in energy for this system is :

dU = 52 kJ

Cricetus

For this process, the change in the energy of the water will be:

"53 kJ".

Heat and Energy

According to the question,

Heat transferred = 65 kJ

Heat loss = 8 kJ

Work done by vapor, dW = 5 kJ

We know,

The resultant heat transferred be:

→ dQ = Heat transferred - Heat loss

         = 65 - 8

         = 57 kJ

By using First law of Thermo-dynamic:

→ dQ = dU + dW

or,

    dU = dQ - dW

By substituting the values,

         = 57 - 5

         = 52 kJ          

Thus the above answer is correct.

Find out more information about heat and energy here:

https://brainly.com/question/12641937

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