Respuesta :
Answer:
Step-by-step explanation:
Given that x = no of movies high school students watched is N(6.8, 1.8)
Sample size = 36 and hence std error = 1.8/6 = 0.3
[tex]H_0: x bar = 6.8\\H_a: x bar < 6.8\\[/tex]
(two tailed test)
Mean difference = 6.2-6.8 = -0.6
Test statistic z = -0.6/0.3= -2
p value = 0.02275
Since p <0.05 we reject H0.
There is evidence to show that college students watch fewer movies a month than high school students
There is sufficient evidence that college students watch fewer movies a month than high school students.
How to test for hypothesis
In order to arrive at a conclusion we have to conduct a statistical test first
The sample size of the [population = 36
standard error = sd/mean
= 1.8/6 = 0.3
We have to calculate the mean difference
= -0.6
The test statistics z = 0.6/.3 = -0.2
Using the test statistics above, we have to find the p value = 0.02275
Given that 0.022 is less than 0.05 we fail to reject the null hypothesis. There is evidence that college students watch fewer movies a month than high school students.
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