A compressed gas cylinder containing 1.50 mol methane has a volume of 3.30 L. What pressure does the methane exert on the walls of the cylinder if its temperature is 25°C?

Respuesta :

Answer:

P=11.126 atm

Explanation:

We are given that a compressed gas cylinder containing 1.50 mol methane

Volume of methane in a gas cylinder =3.3 L

Temperature =[tex]25^{\circ}=25+273.15=298.15 K[/tex]

We have to find the pressure exert by gas on cylinder

Using ideal gas equation

PV =nRT

Where R= gas constant=0.0821 L-atm/K mol

Substitute all given values

Then we get

[tex]P\times 3.3=1.5\times 0.0821\times 298.15[/tex]

[tex]P=\frac{36.717}{3.3}[/tex]

P=11.126 atm

Hence, the pressure exert by the gas on cylinder =11.126 atm

The pressure of the gas is about 11.1 atm

[tex]\texttt{ }[/tex]

Further explanation

The Ideal Gas Law and Work formula that needs to be recalled is:

[tex]\boxed {PV = nRT}[/tex]

[tex]\boxed { W = P \Delta V }[/tex]

where:

W = Work ( J )

P = Pressure ( Pa )

V = Volume ( m³ )

n = number of moles ( moles )

R = Gas Constant ( 8.314 J/mol K )

T = Absolute Temperature ( K )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

amount of substance = n = 1.50 mol

volume of gas = V = 3.30 L

temperature of gas = T = 25 + 273 = 298 K

gas constant = R = 0.0821 L.atm/mol.K

Asked:

pressure of gas = P = ?

Solution:

[tex]PV = n R T[/tex]

[tex]P = n R T \div V[/tex]

[tex]P = 1.50 \times 0.0821 \times 298 \div 3.30[/tex]

[tex]P \approx 11.1 \texttt{ atm}[/tex]

[tex]\texttt{ }[/tex]

Conclusion :

The pressure of the gas is about 11.1 atm

[tex]\texttt{ }[/tex]

Learn more

  • Minimum Coefficient of Static Friction : https://brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

Ver imagen johanrusli