Respuesta :
Answer:
P=11.126 atm
Explanation:
We are given that a compressed gas cylinder containing 1.50 mol methane
Volume of methane in a gas cylinder =3.3 L
Temperature =[tex]25^{\circ}=25+273.15=298.15 K[/tex]
We have to find the pressure exert by gas on cylinder
Using ideal gas equation
PV =nRT
Where R= gas constant=0.0821 L-atm/K mol
Substitute all given values
Then we get
[tex]P\times 3.3=1.5\times 0.0821\times 298.15[/tex]
[tex]P=\frac{36.717}{3.3}[/tex]
P=11.126 atm
Hence, the pressure exert by the gas on cylinder =11.126 atm
The pressure of the gas is about 11.1 atm
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Further explanation
The Ideal Gas Law and Work formula that needs to be recalled is:
[tex]\boxed {PV = nRT}[/tex]
[tex]\boxed { W = P \Delta V }[/tex]
where:
W = Work ( J )
P = Pressure ( Pa )
V = Volume ( m³ )
n = number of moles ( moles )
R = Gas Constant ( 8.314 J/mol K )
T = Absolute Temperature ( K )
Let us now tackle the problem !
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Given:
amount of substance = n = 1.50 mol
volume of gas = V = 3.30 L
temperature of gas = T = 25 + 273 = 298 K
gas constant = R = 0.0821 L.atm/mol.K
Asked:
pressure of gas = P = ?
Solution:
[tex]PV = n R T[/tex]
[tex]P = n R T \div V[/tex]
[tex]P = 1.50 \times 0.0821 \times 298 \div 3.30[/tex]
[tex]P \approx 11.1 \texttt{ atm}[/tex]
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Conclusion :
The pressure of the gas is about 11.1 atm
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Learn more
- Minimum Coefficient of Static Friction : https://brainly.com/question/5884009
- The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
