Answer:
The current in both the wires is 150 A.
Explanation:
It is given that,
Force per unit length between the two wires is given, [tex]\dfrac{F}{l}=0.225\ N/m[/tex]
Let I is the current in the wire when they are separated by 2 cm or 0.02 m
Force per unit length is given by :
[tex]\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}[/tex]
Let [tex]I_1=I_2=I[/tex]
[tex]\dfrac{F}{l}=\dfrac{\mu_o I^2}{2\pi r}[/tex]
[tex]I=\sqrt{\dfrac{F.2\pi r}{\mu_o l}}[/tex]
[tex]I=\sqrt{\dfrac{0.225\times 2\pi \times 0.02}{4\pi \times 10^{-7}}}[/tex]
I = 150 A
So, the current in both the wires is 150 A. Hence, this is the required solution.
