Answer:
The rate of disappearance of [tex]C_2H_4[/tex] is 0.0766 M/s.
Explanation:
[tex]C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(g)[/tex]
Rate of the reaction = R
[tex]R=-\frac{1}{1}\frac{d[C_2H_4]}{dt}=-\frac{1}{3}\frac{d[O_2]}{dt}[/tex]
[te]R=\frac{1}{2}\frac{d[CO_2]}{dt}=\frac{1}{2}\frac{d[H_2O]}{dt}[/tex]
Rate of disappearance of [tex]O_2[/tex] =0.23 M/s
Rate of disappearance of [tex]O_2=3\times R[/tex]
[tex]0.23 M/s=3\times R[/tex]
R =0.07666 M/s
Rate of disappearance of [tex]C_2H_4=1\times R[/tex]
[tex]\frac{d[C_2H_4]}{dt}=1\times 0.23 m/s=0.0766 M/s[/tex]
The rate of disappearance of [tex]C_2H_4[/tex] is 0.0766 M/s.
