Respuesta :
Answer:
Option c) (c) Since the sum of the probabilities is not equal to 1
Step-by-step explanation:
Given is a distribution of a random variable X as
x −3 1 5
P(X=x) 1/2 5/8 3/4
We find that x can take only 3 values as 3,1,5
Since these are countable, this is discrete variable.
Yes. Reason no of values that x can take is countable
b) Each prob lies between 0 and 1.
Total prob = [tex]\frac{1`}{2} +\frac{5`}{8} +\frac{3`}{4} >1[/tex]
Answer is
(c) Since the sum of the probabilities is not equal to 1
A discrete probability is such that only take integer values.
The distribution is not a discrete distribution, since the sum of the probabilities is not equal to 1.
First, we calculate the sum of all probabilities.
For a discrete probability,
[tex]\sum P(x) = 1[/tex]
So, we have:
[tex]\frac 12 + \frac 58 + \frac 34 = 1[/tex]
Express as decimals
[tex]0.50 + 0.625 + 0.75 = 1[/tex]
[tex]1.875 = 1[/tex]
The above equation is not true, because:
[tex]1.875 \ne 1[/tex]
This means that: the distribution is not a discrete distribution, since the sum of the probabilities is not equal to 1.
Hence, (c) is true
Read more about discrete probabilities at:
https://brainly.com/question/17145091