Answer:
5 orders of (6 sticks ) + 4 orders of (3 sticks) = 42
Step-by-step explanation:
42 = 3(small) + 6(large)
also, 1 large = 2small
42 = 3s + 6(2s)
42 = 3s + 12s
42 = 15s
42/15 = 2.8 close to 3.
3(3) + 6(l) = 42
9 + 6(l) = 42
6(l) = 42 -9
l = 33/6 = 5.5 close to 5
5(6) + 4(3) = 42
Not sure if this makes entire sense ...
For this case we have to:
x: Represents an order of small sticks
y: Represents an order of large sticks
We have to:
[tex]x + y = 9\\3x + 6y = 42[/tex]
From the first equation we have to:
[tex]x = 9-y[/tex]
Substituting in the second:
[tex]3 (9-y) + 6y = 42\\27-3y + 6y = 42\\3y = 42-27\\3y = 15\\y = \frac {15} {3}\\y = 5[/tex]
Thus, he obtained 5 times the order of large sticks.
Answer:
5 times
