Answer: 135 grams of sugar.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{Number of moles of carbon dioxide=\frac{200g}{44g/mol}=4.5moles[/tex]
[tex]CO_2[/tex] acts as limiting reagent as it limits the formation of product.
[tex]6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2[/tex]
According to stoichiometry:
6 mole of [tex]CO_2[/tex] reacts to give 1 mole of sugar
Thus 4.5 moles of [tex]CO_2[/tex] will react to give=[tex]\frac{1}{6}\times 4.5=0.75[/tex] moles of sugar
Mass of [tex]C_6H_{12}O_6=moles\times Molar mass=0.75moles\times 180g/mol=135grams[/tex]
Thus 135 grams of sugar can be created.
