The area for the perimeter of a rectangle is:
P = 2l + 2w
In this problem, we are given that P = 155 and l = 45.5. To solve for area, we must find w. To do this, plug in the given info and isolate the w like so:
[tex]155=2(45.5)+2w \\ 155=91+2w \\ (155)-91=(91+2w)-91 \\ 64=2w \\ \frac{64}{2} = \frac{2w}{2} \\ w=32[/tex]
Now we know w = 32. Knowing all the necessary info, we can use the area formula, A=lw, to solve for A.
[tex]A=(45.5)(35) \\ A=1,456[/tex]
The area is 1,456 sq ft.
Hope this helps!
