Answer:
5.112 grams of simple sugar glucose is produced by the reaction of 7.50 g of carbon dioxide.
Explanation:
[tex]6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2[/tex]
Moles of carbon dioxide = [tex]\frac{7.50 g}{44 g/mol}=0.1704 mol[/tex]
According to reaction 6 moles of carbon dioxide gives 1 mole of glucose.
Then 0.1704 moles of carbon dioxide will give:
[tex]\frac{1}{6}\times 0.1704 mol=0.0284 mol[/tex] of glucose
Mass of 0.0284 moles of glucose:
0.0284 mol 180 g/mol =5.112 g[/tex]
5.112 grams of simple sugar glucose is produced by the reaction of 7.50 g of carbon dioxide.
