Answer:
Step-by-step explanation:
Let X be the average of tennis balls.
mu = 55.4 inches
Hypotheses:
H_0: x bar = 55.4\\
H_a: x bar \neq 55.4
(Two tailed test at 10% significance level)
n = 25: x bar = 56.6 and s = 0.25
STd error =s/sqrt 25 = 0.05
Mean diff = 56.6-55.4 = 1.2"
t statistic = 1.2/0.05 = 24
df= 24
t critical value = ±1.318
Since t statistic lies outside this we reject null hypothesis
The company does not manufacture acceptable tennis balls and this is evidence at 90% confidence interval