Answer:
ω = 2.9 rad/s, v = 31.7 m/s, α = 0.78 rad/s², a = 91,6 m/s²
Explanation:
I will assume the given equation reads as Ф = 0.39t².
The angular velocity ω is the time derivative of Ф.
ω = 0.78t
The linear velocity v is given by ωr, where r is the radius of the centrifuge.
v = 0.78t r
The tangential acceleration α is the time derivative of ω.
α = 0.78
The radial acceleration a is given by: a = ω²r
a = (0.78t)²r