A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident green light (wavelength 500 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.

Respuesta :

Answer:

The thickness of the oil slick is [tex]1.95\times10^{-7}\ m[/tex]

Explanation:

Given that,

Index of refraction = 1.28

Wave length = 500 nm

Order m = 1

We need to calculate the thickness of oil slick

Using formula of thickness

[tex]2nt= m\lambda[/tex]

Where, n = Index of refraction

t = thickness

[tex]\lambda[/tex] = wavelength

Put the value into the formula

[tex]2\times1.28 \times t=1\times\times500\times10^{-9}[/tex]

[tex]t = \dfrac{1\times\times500\times10^{-9}}{2\times1.28 }[/tex]

[tex]t=1.95\times10^{-7}\ m[/tex]

Hence, The thickness of the oil slick is [tex]1.95\times10^{-7}\ m[/tex]