Answer:
The equation of two curves are
[tex]1.\rightarrow y=(x+3)^2+4\\\\2.y=(x+1)^2+6[/tex]
If you will draw the graph of two function, you will note that
Parabola 1 , has vertex (-3,4) and, Parabola 2, has vertex (-1,6).
Transformation means Translation of Parabola 1, has taken place to obtain Parabola 2.
-3 +2 = -1
4+2=6
----Parabola 1, has been translated 2, units Horizontally right and 2 units Vertically up to obtain Parabola 2.
We can find it's point of Intersection in following way.
[tex]\rightarrow (x+3)^2+4=(x+1)^2+6\\\\ x^2+6x+9+4=x^2+2x+1+6\\\\\text{Adding and subtracting like terms}\\\\6x-2x=7-13\\\\4x=-6\\\\x=\frac{-6}{4}\\\\x=\frac{-3}{2}\\\\y=(\frac{-3}{2}+1)^2+6\\\\y=(\frac{-1}{2})^2+6\\\\y=6+\frac{1}{4}\\\\y=\frac{25}{4}[/tex]
Point of Intersection of two Parabola are
[tex](\frac{-3}{2},\frac{25}{4})[/tex]
