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A pair of slits, separated by 0.150 mm, is illuminated by light having a wavelength of λ = 643 nm. An interference pattern is observed on a screen 140 cm from the slits. Consider a point on the screen located at y = 1.80 cm from the central maximum of this pattern. What is the path difference δ for the two slits at the location y?

Respuesta :

Answer:

0.006 m

Explanation:

d = separation between the slits = 0.150 mm = 0.150 x 10⁻³ m

λ = wavelength of the light = 643 nm = 643 x 10⁻⁹ m

D = distance of the screen where interference pattern is observed = 140 cm = 1.40 m

δ = Path difference

Path difference is given as

δ = Dλ/d

δ = (1.40) (643 x 10⁻⁹)/(0.150 x 10⁻³)

δ = 0.006 m

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