Answer:
Volume rate of flow through the pipe is 1.457 × 10⁻⁵ m³/s
Explanation:
Given:
Inner diameter of the tube, d = 2.5 mm = 2.5 × 10⁻³ m
water level above the hole, h = 45 cm = 0.45 m
now,
the velocity of the water at the level of hole, v = √(2gh)
thus,
v = √(2 × 9.8 ×.45)
or
v = 2.969 m/s
Now,
the discharge (Q) is given as:
Q = Area × velocity
area of the outlet = πd²/4
or
area = π(2.5 × 10⁻³)²/4 = 4.90 × 10⁻⁶ m²
on substituting the values in the formula for discharge, we get
Q = 4.90 × 10⁻⁶ m² × 2.969 m/s
or
Q = 1.457 × 10⁻⁵ m³/s
hence, the volume rate of flow through the pipe is 1.457 × 10⁻⁵ m³/s
