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Two slits separated by 0.425 mm are illuminated with light of an unknown wavelength and an interference pattern is observed on a screen 3.13 m away. The tenth bright line is 49.1 mm from the central maximum. The wavelength of the light is nm?

Respuesta :

Answer:

wavelength is 666.6933 × [tex]10^{-9}[/tex] m

Explanation:

given data

Two slits separated d = 0.425 mm

screen away D =  3.13 m

tenth bright line (y) = 49.1 mm

to find out

The wavelength of the light

solution

let angle θ at which bright fringed occurs

so that

tanθ =   y / D

here D id slits to screen distance and  tanθ = θ

and

construction interference equation

sinθ  = m β / d

and here sinθ  = θ and β is wavelength

θ = m β / d

and

θ = m β / d

y / D = m β / d

β =  y d / Dm

wavelength = 49.1 [tex]10^{-3}[/tex] × 0.425  [tex]10^{-3}[/tex]   / 3.13 (10)

wavelength = 49.1 [tex]10^{-3}[/tex] × 0.425  [tex]10^{-3}[/tex]   / 3.13 (10)

wavelength is 666.6933 × [tex]10^{-9}[/tex] m

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