According to the Heisenberg uncertainty principle, if the uncertainty in the speed of an electron is 3.5 × 103 m/s, the uncertainty in its position (in m) is at least:

Respuesta :

Explanation:

It is given that,

Uncertainty in the speed of an electron, [tex]\Delta v=3.5\times 10^3\ m/s[/tex]

According to Heisenberg uncertainty principle,

[tex]\Delta x.\Delta p=\dfrac{h}{4\pi}[/tex]

[tex]\Delta x[/tex] is the uncertainty in the position of an electron

Since, [tex]\Delta p=m\Delta v[/tex]

[tex]\Delta x=\dfrac{h}{4\pi.m \Delta v}[/tex]

[tex]\Delta x=\dfrac{6.6\times 10^{-34}}{4\pi\times 9.1\times 10^{-31}\times 3.5\times 10^3}[/tex]

[tex]\Delta x=1.64\times 10^{-8}\ m[/tex]

So, the uncertainty in its position is [tex]1.64\times 10^{-8}\ m[/tex]. Hence, this is the required solution.