If the specific heat capacity of water is 4.18 J/g·oC , how much of heat energy is needed to raise the temperature of 10.00 g of liquid water from 14.1 oC to 16.2 oC?

Respuesta :

Explanation:

As it is known that relation between specific heat and heat energy is as follows.

               Q = [tex]mC \Delta T[/tex]

where,          Q = heat energy

                     m = mass

                     C = specific heat capacity = 4.18 [tex]J/g ^{o}C[/tex]

                 [tex]\Delta T[/tex] = change in temperature

Therefore, putting the given values into the above formula as follows.

                      Q = [tex]mC \Delta T[/tex]

                          = [tex]10 g \times 4.18 J/g ^{o}C \times (16.2 - 14.1)^{o}C[/tex]

                          = 87.78 J

Thus, we can conclude that the heat energy needed to raise the temperature of 10.00 g of liquid water from [tex]14.1^{o}C[/tex] to [tex]16.2^{o}C[/tex] is 87.78 J.