in ∆ABC, AB is extended through D, m<CBD =30 and AB = BC. What is the measure of angle a

Answer:
15°
Step-by-step explanation:
∠ABC and ∠DBC form a straight angle and are supplementary, thus
∠ABC + 30 = 180 ( subtract 30 from both sides )
∠ABC = 150°
Since AB = BC then ΔABC is isosceles with ∠BAC = ∠BCA
The sum of the 3 angles in the triangle = 180°
Hence ∠BAC = [tex]\frac{180-150}{2}[/tex] = [tex]\frac{30}{2}[/tex] = 15
That is ∠a = 15°