Answer: Our required probability is 39.69%.
Step-by-step explanation:
Since we have given that
Probability of a bowler getting a strike during a particular frame = 63%
Number of frames are performed = 2
We need to find the probability that the bowler would be most likely to get a strike in each of the two frames.
So, it becomes,
[tex]\dfrac{63}{100}\times \dfrac{63}{100}=(0.63)^2\\\\=0.3969\\\\=39.69\%[/tex]
Hence, Our required probability is 39.69%.