Cesium-137 has a half-life of about 30 years. Given this half-life, we can represent its decay with the exponential decay function A=A0e(ln(0.5)30)t If we begin with 200 mg of cesium-137, how long will it take for the Cesium to decay to the point where there is only 1 milligram remaining? Round to the closest year.

Respuesta :

Answer: 229 years

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Half life for first order kinetics is given by:

[tex]t_{\frac{1}{2}=\frac{0.693}{k}[/tex]

[tex]t_{\frac{1}{2}[/tex] = half life = 30 years

k = rate constant =?

[tex]30years=\frac{0.693}{k}[/tex]

[tex]k=0.0231years^{-1}[/tex]

Integrated rate law for first order kinetics is given as:

[tex]A=A_0e^{-kt}[/tex]

k = rate constant of the reaction

[tex][A_o][/tex] = Concentration of reactant initially = 200 mg

[tex][A][/tex] = Concentration of reactant at time t = 1 mg

[tex]1=200e^{-0.0231\times t}[/tex]

[tex]t=229years[/tex]

Thus time take for the Cesium to decay to the point where there is only 1 milligram remaining is 229 years.