Explanation:
The ratio of concentration of products divided by the concentration of reactants at equilibrium is known as equilibrium constant. It is represented as [tex]K_{eq}[/tex].
As the given reaction is as follows.
[tex]2A \rightleftharpoons B[/tex]
Hence, the equilibrium constant for the same will be as follows.
[tex]K_{eq} = \frac{[B]}{[A]^{2}}[/tex]
= [tex]\frac{0.12}{(0.056)^{2}}[/tex]
= 38
Thus, we can conclude that the equilibrium constant ([tex]K_eq[/tex] ) for the reaction is 38.
