Respuesta :
Answer:
14.32 Hz
Explanation:
Given:
Frequency of the horn, f₀ = 395 Hz
Speed of the car, v = 12.0 m/s
Speed of the sound, c = 343 m/s
now, applying the doppler's effect formula, we have
[tex]f=f_0(\frac{c}{c-v})[/tex]
where,
f is the observed frequency
on substituting the values, we get
[tex]f=395\times(\frac{343}{343-12})[/tex]
or
f = 409.32 Hz
therefore,
the beat frequency heard is = f - f₀ = 409.32 - 395 = 14.32 Hz
Answer:
The beat frequency heard by the bystander is 14.32 Hz
Explanation:
Given that,
Emitting frequency = 395 Hz
Speed of cars = 12.0 m/s
Speed of sound = 343 m/s
We need to calculate the frequency
Using formula of frequency
[tex]f=\dfrc{v}{v'-v}\times f_{0}[/tex]
Where, v = speed of sound
v' = speed of cars
f₀= emitting frequency
Put the value into the formula
[tex]f=\dfrac{343}{343-12}\times395[/tex]
[tex]f=409.32\ Hz[/tex]
We need to calculate the beat frequency heard by the bystander
[tex]f'=f-f_{0}[/tex]
[tex]f'=409.32-395[/tex]
[tex]f'=14.32\ Hz[/tex]
Hence, The beat frequency heard by the bystander is 14.32 Hz.
