Respuesta :
Answer:
The velocity of the truck after this elastic collision is 15.7 m/s
Explanation:
It is given that,
Mass of the car, [tex]m_1=1.1\times 10^3\ kg[/tex]
Mass of the truck, [tex]m_2=2.3\times 10^3\ kg[/tex]
Initial velocity of the car, [tex]u_1=22\ m/s[/tex]
Initial velocity of the truck, u₂ = 0
After the collision the velocity of the car is, v₁ = -11 m/s
Let v₂ is the velocity of the truck after this elastic collision. Using the conservation of momentum as :
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]1.1\times 10^3\times 22+0=1.1\times 10^3\times (11)+2.3\times 10^3\times v_2[/tex]
[tex]v_2=15.7\ m/s[/tex]
So, the velocity of the truck after this elastic collision is 15.7 m/s. Hence, the correct option is (c).
