Respuesta :
Answer:
Empirical formula = NS
Molecular formula = N₄S₄
Explanation:
Since, the compound only contain nitrogen and sulfur,
Thus ,
Name of the element % moles Simplest ratio
S 69.6 69.6/32 = 2.17 1
N 100 - 69.6 = 30.4 30.4/14 = 2.17 1
Hence, the empirical formula = NS
The molar mass of the compound : 184 g/mol
So,
x ( 32 +14 ) = 184
x = 4
So, Molecular formula = N₄S₄
a. The empirical formula of the chemical compound is [tex]NS[/tex]
b. The molecular formula of the chemical compound is [tex]N_4S_4[/tex]
Given the following data:
- Molar mass = 184 g/mol
- Percentage by mass of sulfur (S) = 69.6%
To find the empirical and molecular formulas of the chemical compound:
First of all, we would determine the percentage by mass of nitrogen (N).
%N [tex]= 100 - 69.6[/tex]
%N = 30.4
For empirical formula:
[tex]\frac{69.6}{32} = \frac{30.4}{14} = 2.02 = 2.02 = 1:1 = NS[/tex]
- The atomic weight of N = 14 g/mol
- The atomic weight of S = 32 g/mol
Next, we would determine the mass and number of moles of sulfur and nitrogen:
For sulfur:
[tex]Mass = \frac{69.6}{100} \times 184\\\\Mass = \frac{12806.4}{100}[/tex]
Mass = 128.064 grams
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{128.064}{32}[/tex]
Number of moles = 4.0 moles
For nitrogen:
[tex]Mass = \frac{30.4}{100} \times 184\\\\Mass = \frac{5593.6}{100}[/tex]
Mass = 55.936 grams
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{55.936}{14}[/tex]
Number of moles = 4.0 moles
Therefore, the molecular formula of the chemical compound is [tex]N_4S_4[/tex]
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