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A linearly polarized electromagnetic wave has an average intensity of I0. This wave is incident on a polarizer. What angle between the axis of polarization of the polarizer and the direction of polarization of the incident light will result in an average intensity of light leaving the polarizer of 0.21·I0?

Respuesta :

Answer:

62.73 degree

Explanation:

According to law of Malus

[tex]I = I_{0}Cos^{2}\theta[/tex]

Where, θ be the angle between axis of polarisation of polariser

[tex]0.21I_{0} = I_{0}Cos^{2}\theta[/tex]

Cosθ = 0.4583

θ = 62.73 degree

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