An emf is induced by rotating a 1000-turn, 20.0 cm diameter coil in the Earth’s 5.00×10−5T magnetic field. What average emf is induced, given the plane of the coil is originally perpendicular to the Earth’s field and is rotated to be parallel to the field in 10.0 ms?

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Answer:

0.157 Volts

Explanation:

N = Number of turns ion the coil = 1000

d = diameter = 20 cm = 0.2 m

Area of the coil is given as

A = (0.25) πd² = (0.25) (3.14) (0.2)² = 0.0314 m²

t = time interval = 10 ms = 0.01 s

ΔB = Change in magnetic field = 0 - 5 x 10⁻⁵ T  =  - 5 x 10⁻⁵ T

Average induced emf is given as

E = - N ΔBA/t

E = - (1000) (- 5 x 10⁻⁵ ) (0.0314)/(0.01)

E = 0.157 Volts

The average emf induced in the coil due to Earth's magnetic filed is 0.157 volts.

What is emf (electromotive force)?

Emf or electromotive force is the potential generated by changing the magnetic filed. The emf induced can be find out using the following formula,

[tex]E=-N\dfrac{\Delta B\times A}{t}[/tex]

Here, (N) is the number of turns in the coil, (A) is the cross sectional area or coil and (t) is the time.

The number of turns in the coil is 1000-turn,

As the diameter of the coil is 20.0 cm. Thus the cross sectional area of the coil is given as,

[tex]A=\dfrac{0.2^2}{4}\times\pi\\A=0.0314\rm m^2[/tex]

Thus, the cross sectional area of the coil is 0.314 m².

As the Earth’s magnetic field is 5.00×10−5T and the time interval of rotation is 10.0 ms. Thus the average emf induced in the coil due to Earth's magnetic filed is,

[tex]E=-1000\dfrac{0-5\times10^{-5}\times0.0314}{0.01}\\E=0.157\rm Volts[/tex]

Thus, the average emf induced in the coil due to Earth's magnetic filed is 0.157 volts.

Learn more about the emf here;

https://brainly.com/question/1176850