The needed conjugate of quotient as:
[tex]\overline{z} = \dfrac{12}{13} + \dfrac{8}{13}i[/tex]
The given complex numbers are:
[tex]z_1 = 0 - 4i\\z_2 = 2 - 3i[/tex]
Their quotient is calculated as:
[tex]\dfrac{z_1}{z_2} = \dfrac{0 - 4i}{2 - 3i}\\\\= \dfrac{(0-4i)(2+3i)}{(2-3i)(2+3i)}\\\\= \dfrac{(-8i-12i^2)}{(4 - 9i^2)}\\\\= \dfrac{12 - 8i}{4+9}\\\\= \dfrac{12}{13} -\dfrac{8}{13}i\\\\= z ( say)[/tex]
We used rationalization to simplify the quotient. It is done by multiplying and dividing by same factor so as to simplify the given fraction.
It is the property of iota that [tex]i^2 = -1[/tex]
Now conjugate of z is
[tex]\overline{z} = \dfrac{12}{13} + \dfrac{8}{13}i[/tex]
Thus we have needed conjugate of quotient as:
[tex]\overline{z} = \dfrac{12}{13} + \dfrac{8}{13}i[/tex]
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