Answer:
[tex]\boxed{\text{2.274 mol/L}}[/tex]
Explanation:
[tex]b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}[/tex]
Assume 1 kg water.
1. Moles of P.HCl
Then we have 4.666 mol of P.HCl
2. Mass of P.HCl
n = 4.666 mol × 272.77 g/mol = 1271.1 g
3. Total mass of solution
m = 1000 g + 1271.1 g = 2271.1 g solution
4. Volume of solution
[tex]V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}[/tex]
5. Molar concentration
[tex]\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\[/tex]
[tex]\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}[/tex]
The molarity of the solution is 2.272 mol/L
The molarity of a solution can be defined as the dissolution of the number of moles of solute divided by the 1 liter of the solution.
Given that:
the number of moles of Procaine hydrochloride = 4.666 moles
The relation for determining the number of moles = mass/molar mass
mass = no of moles × molar mass
mass = 4.666 mol × 272.77 g/mol
mass of Procaine hydrochloride = 1272.75 g
The total mass of the solution in a 1000 gram solution will be:
= 1272.75 g + 1000 g
= 2272.75 g of solution
The volume of the solution can now be estimated as:
[tex]\mathbf{V = \dfrac{2272.75 \ g }{1.1066 \ g/mL}}[/tex]
V = 2053.81 mL
V = 2.0538 L
∴
The molarity(molar concentration C) of the solution can be computed as follows:
[tex]\mathbf{C = \dfrac{moles \ of \ solute}{solution (L)}}[/tex]
[tex]\mathbf{C = \dfrac{4.666 \ mol}{2.0538 \ L}}[/tex]
C = 2.272 mol/L
Therefore, we can conclude that the molarity of the solution is 2.272 mol/L
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