Answer:
[tex]\large\boxed{g(-1)=4}[/tex]
Step-by-step explanation:
In this question. we would be plugging in -1 to all of the x variables.
The equation we are solving is:
[tex]g(x)=\frac{3x^2-2x+7}{2x+5}[/tex]
You would plug in -1 to all of the x variables.
Your equation should look like this:
[tex]g(x)=\frac{3(-1)^2-2(-1)+7}{2(-1)+5}[/tex]
Now, you solve:
[tex]g(x)=\frac{3(-1)^2-2(-1)+7}{2(-1)+5}\\\\\text{Lets start with the top}\\\\g(x)=\frac{3(1)-2(-1)+7}{2(-1)+5}\\\\g(x)=\frac{3-2(-1)+7}{2(-1)+5}\\\\g(x)=\frac{3+2+7}{2(-1)+5}\\\\g(x)=\frac{12}{2(-1)+5}\\\\\text{We can do the bottom now}\\\\g(x)=\frac{12}{2(-1)+5}\\\\g(x)=\frac{12}{-2+5}\\\\g(x)=\frac{12}{3}\\\\\text{Divide the fraction}\\\\g(-1)=4[/tex]
When you're done solving, you should get 4.
This means that when g is -1, the answer would be 4.
g(-1) = 4
I hope this helped you out.
Good luck on your academics.
Have a fantastic day!
