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A horizontal surface of area 0.321 m2has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the latter.

Respuesta :

Answer:

electric filed is 907 N/C

Explanation:

Given data

surface of area = 0.321 m²

electric flux of 123 N.m²/C

angle = 25°

to find out

magnitude of the electric field

solution

we know flux formula that is

flux = electric filed × area

put all value

123 = electric filed × 0.321 sin(25)

electric filed = 123 /  0.321 sin(25)

electric filed = 906.67

so electric filed is 907 N/C

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