Respuesta :
For this case we have the following system of equations:
[tex]12x + 6y = 120\\4x + y = 30[/tex]
We must solve the system by the method of elimination. To do this we multiply the second equation by -3, then:
[tex]12x + 6y = 120\\-12x-3y = -90[/tex]
We add both equations:
[tex]12x-12x + 6y-3y = 120-90\\3y = 30\\y = \frac {30} {3}\\y = 10[/tex]
We find the value of "x":
[tex]4x + y = 304x + 10 = 30\\4x = 30-10\\4x = 20\\x = \frac {20} {4}\\x = 5[/tex]
Thus, the solution of the system is:
[tex](x, y) :( 5,10)[/tex]
We verify:
[tex]12 (5) +6 (10) = 120\\60 + 60 = 120\\120 = 120[/tex]
Is fulfilled!
[tex]4 (5) + 10 = 30\\20 + 10 = 30\\30 = 30[/tex]
Is fulfilled!
Answer:
[tex](x, y) :( 5,10)[/tex]