Respuesta :
Answer:
B
Step-by-step explanation:
B. This means that the actual percentage of patients that experience flulike symptoms during December can be somewhere between 74% - 3.2% and 74% + 3.2%, so between 70.8% and 77.2%.
The figures given from the study means: Option B: The confidence interval is between 70.8% and 77.2%.
How to find the confidence interval from sample proportion and margin of error?
Suppose that we get:
- Sample proportion = [tex]\hat{p}[/tex]
- margin of error = [tex]MOE[/tex]
Then, the confidence interval for that variable would be:
[tex]CI = [\hat{p} - MOE, \hat{p} + MOE][/tex]
For this case, we're specified that:
Sample proportion of people experiencing flulike symptoms = 74%
= 0.74 (converted percent to decimal) = [tex]\hat{p}[/tex]
Margin of error for the population proportion (proportion that will be found in the population of those who have flulike symptoms) = 3.2% = MOE
Thus, the confidence interval for the values of the population proportion at the confidence level for which margin of error was calculated, from the sample study is obtained as:
[tex]CI = [\hat{p} - MOE, \hat{p} + MOE]\\CI = [74\% - 3.2\%, 74\% + 3.2\%]\\CI = [70.8\%, 77.2\%][/tex]
Thus, the figures given from the study means: Option B: The confidence interval is between 70.8% and 77.2%.
Learn more about confidence interval here:
https://brainly.com/question/16427118
