To win a loto in one state, one must correctly select 7 numbers from a collection of 48 numbers (1 through 48). The order in which the selection is made does not matter. How many different selections are possible?

Respuesta :

Answer:

[tex]48C7=73,629,072\ ways[/tex]

Step-by-step explanation:

Since the order in which you select the numbers is not important then we have a combination problem

The formula of combinations is:

[tex]nCr=\frac{n!}{r!(n-r)!}[/tex]

Where n is the number of objects you can choose, and you choose r from them

Then you will get the number of possible ways to select r objects from a group of n objects

In this case we have that:

[tex]n=48\\\\r=7[/tex]

Therefore:

[tex]48C7=\frac{48!}{7!(48-7)!}[/tex]

[tex]48C7=\frac{48!}{7!*41!}[/tex]

[tex]48C7=\frac{48*47*46*45*44*43*42*41!}{7*6*5*4*3*2*1*41!}[/tex]

[tex]48C7=\frac{48*47*46*45*44*43*42}{7*6*5*4*3*2*1}[/tex]

[tex]48C7=73,629,072\ ways[/tex]

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